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80 lines (71 loc) · 2.54 KB
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<?php
namespace App;
use SplQueue;
/**
* Course Schedule II
*
* There are a total of numCourses courses you have to take, labeled from 0 to numCourses - 1. You are given an array
* prerequisites where prerequisites[i] = [a_i, b_i] indicates that you must take course b_i first if you want to take
* course a_i.
* For example, the pair [0, 1], indicates that to take course 0 you have to first take course 1.
* Return the ordering of courses you should take to finish all courses. If there are many valid answers, return any of
* them. If it is impossible to finish all courses, return an empty array.
*
* Example 1:
* Input: numCourses = 2, prerequisites = [[1,0]]
* Output: [0,1]
* Explanation: There are a total of 2 courses to take. To take course 1 you should have finished course 0. So the
* correct course order is [0,1].
*
* Example 2:
* Input: numCourses = 4, prerequisites = [[1,0],[2,0],[3,1],[3,2]]
* Output: [0,2,1,3]
* Explanation: There are a total of 4 courses to take. To take course 3 you should have finished both courses 1 and 2.
* Both courses 1 and 2 should be taken after you finished course 0.
* So one correct course order is [0,1,2,3]. Another correct ordering is [0,2,1,3].
*
* Example 3:
* Input: numCourses = 1, prerequisites = []
* Output: [0]
*
* https://leetcode.com/problems/course-schedule-ii
*/
class CourseScheduleII
{
/**
* @param int $numCourses
* @param array $prerequisites
* @return array
*/
public function findOrder(int $numCourses, array $prerequisites): array
{
$graph = [];
$inDegree = array_fill(0, $numCourses, 0);
$queue = new SplQueue();
$result = [];
/** @var array<array-key, int> $prerequisite */
foreach ($prerequisites as $prerequisite) {
$graph[$prerequisite[1]][] = $prerequisite[0];
$inDegree[$prerequisite[0]]++;
}
for ($i = 0; $i < $numCourses; $i++) {
if ($inDegree[$i] === 0) {
$queue->enqueue($i);
}
}
while (!$queue->isEmpty()) {
/** @var int $course */
$course = $queue->dequeue();
$result[] = $course;
if (isset($graph[$course])) {
foreach ($graph[$course] as $neighbor) {
$inDegree[$neighbor]--;
if ($inDegree[$neighbor] === 0) {
$queue->enqueue($neighbor);
}
}
}
}
return count($result) === $numCourses ? $result : [];
}
}