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<?php
namespace App;
/**
* Find Numbers with Even Number of Digits
*
* Given an array nums of integers, return how many of them contain an even number of digits.
*
* Example 1:
* Input: nums = [12,345,2,6,7896]
* Output: 2
* Explanation:
* 12 contains 2 digits (even number of digits).
* 345 contains 3 digits (odd number of digits).
* 2 contains 1 digit (odd number of digits).
* 6 contains 1 digit (odd number of digits).
* 7896 contains 4 digits (even number of digits).
* Therefore, only 12 and 7896 contain an even number of digits.
*
* Example 2:
* Input: nums = [555,901,482,1771]
* Output: 1
* Explanation:
* Only 1771 contains an even number of digits.
*
* https://leetcode.com/problems/find-numbers-with-even-number-of-digits
*/
class FindNumbersWithEvenNumberOfDigits
{
/**
* @param array<array-key, int> $nums
* @return int
*/
public function findNumbers(array $nums): int
{
$evenDigits = 0;
foreach ($nums as $num) {
$numDigits = $this->findNumberOfDigits($num);
if ($numDigits % 2 === 0) {
$evenDigits++;
}
}
return $evenDigits;
}
private function findNumberOfDigits(int $number): int
{
$numDigits = 0;
while ($number > 0) {
$number = (int)($number / 10);
$numDigits++;
}
return $numDigits;
}
}