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<?php
namespace App;
/**
* Number Of Rectangles That Can Form The Largest Square
*
* You are given an array rectangles where rectangles[i] = [l_i, w_i] represents the ith rectangle of length l_i and
* width w_i. You can cut the i-th rectangle to form a square with a side length of k if both k <= l_i and k <= w_i.
* For example, if you have a rectangle [4,6], you can cut it to get a square with a side length of at most 4.
* Let maxLen be the side length of the largest square you can obtain from any of the given rectangles.
* Return the number of rectangles that can make a square with a side length of maxLen.
*
* Example 1:
* Input: rectangles = [[5,8],[3,9],[5,12],[16,5]]
* Output: 3
* Explanation: The largest squares you can get from each rectangle are of lengths [5,3,5,5].
* The largest possible square is of length 5, and you can get it out of 3 rectangles.
*
* https://leetcode.com/problems/number-of-rectangles-that-can-form-the-largest-square
*/
class NumberOfRectangles
{
/**
* @param array<array-key, int> $rectangles
* @return int
*/
public function countGoodRectangles(array $rectangles): int
{
$largestSquares = [];
$maxSquare = PHP_INT_MIN;
/** @var array<array-key, int> $rectangle */
foreach ($rectangles as $rectangle) {
$largestPossibleSquare = min($rectangle[0], $rectangle[1]);
$largestSquares[] = $largestPossibleSquare;
if ($maxSquare < $largestPossibleSquare) {
$maxSquare = $largestPossibleSquare;
}
}
$goodRectangles = 0;
foreach ($largestSquares as $largestSquare) {
if ($largestSquare === $maxSquare) {
$goodRectangles++;
}
}
return $goodRectangles;
}
}