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<?php
namespace App;
/**
* Split With Minimum Sum
*
* Given a positive integer num, split it into two non-negative integers num1 and num2 such that:
* - The concatenation of num1 and num2 is a permutation of num.
* - In other words, the sum of the number of occurrences of each digit in num1 and num2 is equal to the number of
* occurrences of that digit in num.
* - num1 and num2 can contain leading zeros.
* Return the minimum possible sum of num1 and num2.
* Notes: It is guaranteed that num does not contain any leading zeros. The order of occurrence of the digits in num1
* and num2 may differ from the order of occurrence of num.
*
* Example 1:
* Input: num = 4325
* Output: 59
* Explanation: We can split 4325 so that num1 is 24 and num2 is 35, giving a sum of 59. We can prove that 59 is indeed
* the minimal possible sum.
*
* Example 2:
* Input: num = 687
* Output: 75
* Explanation: We can split 687 so that num1 is 68 and num2 is 7, which would give an optimal sum of 75.
*
* https://leetcode.com/problems/split-with-minimum-sum
*/
class SplitWithMinimumSum
{
/**
* @param int $num
* @return int
*/
public function splitNum(int $num): int
{
$copy = array_map('intval', str_split((string) $num));
sort($copy);
$num1 = 0;
$num2 = 0;
for ($i = 0, $iMax = count($copy); $i < $iMax; $i++) {
if ($i % 2 === 0) {
$num1 = $num1 * 10 + $copy[$i];
} elseif ($i % 2 !== 0) {
$num2 = $num2 * 10 + $copy[$i];
}
}
return $num1 + $num2;
}
}