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<?php
namespace App;
/**
* Intersection of Two Arrays II
*
* Given two integer arrays nums1 and nums2, return an array of their intersection. Each element in the result must
* appear as many times as it shows in both arrays and you may return the result in any order.
*
* Example 1:
* Input: nums1 = [1,2,2,1], nums2 = [2,2]
* Output: [2,2]
*
* Example 2:
* Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4]
* Output: [4,9]
*
* https://leetcode.com/problems/intersection-of-two-arrays-ii
*/
class TwoArraysIntersectionII
{
/**
* @param array<array-key, int> $nums1
* @param array<array-key, int> $nums2
* @return array<array-key, int>
*/
public function intersect(array $nums1, array $nums2): array
{
$nums1Hash = $this->createHash($nums1);
$nums2Hash = $this->createHash($nums2);
$intersections = [];
foreach ($nums1Hash as $num1Key => $num1Value) {
if (isset($nums2Hash[$num1Key])) {
$repeatNum = min($nums2Hash[$num1Key], $num1Value);
for ($i = 1; $i <= $repeatNum; $i++) {
$intersections[] = (int) $num1Key;
}
}
}
return $intersections;
}
/**
* @param array<array-key, int> $nums
* @return array<array-key, int>
*/
private function createHash(array $nums): array
{
$numsHash = [];
foreach ($nums as $num) {
if (isset($numsHash[$num])) {
$numsHash[$num]++;
} else {
$numsHash[$num] = 1;
}
}
return $numsHash;
}
}