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Copy path1508. Range Sum of Sorted Subarray Sums
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1508. Range Sum of Sorted Subarray Sums
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72 lines (48 loc) · 1.17 KB
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class Solution
{
int MOD = (int)1e9+7;
public int rangeSum(int[] nums, int n, int left, int right)
{
int[] arr= new int[n*(n+1)/2];
for(int i=0,k=0;i<n;i++)
{
int sum=0;
for(int j=i;j<n;j++)
{
sum+=nums[j];
arr[k++]=sum;
}
}
Arrays.sort(arr);
int sum=0;
for(int i=left;i<=right;i++)
{
sum=(sum+arr[i-1]) % MOD;
}
return sum;
}
/*
Runtime 170 ms, Memory 72.43 MB
static int MOD = 1000000007;
public int rangeSum(int[] nums, int n, int left, int right)
{
ArrayList<Integer> subArrSum = new ArrayList<>();
long rangeSum = 0;
for(int i=0; i<n; i++)
{
int sum=0;
for(int j=i; j<n; j++)
{
sum += nums[j];
subArrSum.add(sum);
}
}
Collections.sort(subArrSum);
for(int i=left-1; i< right; i++)
{
rangeSum = (rangeSum + subArrSum.get(i)) % MOD;
}
return (int)rangeSum;
}
*/
}