Skip to content

Implement BFS-2-1: Rotting Oranges and Employee Importance#642

Open
ashutosh-das-id wants to merge 1 commit into
super30admin:mainfrom
ashutosh-das-id:main
Open

Implement BFS-2-1: Rotting Oranges and Employee Importance#642
ashutosh-das-id wants to merge 1 commit into
super30admin:mainfrom
ashutosh-das-id:main

Conversation

@ashutosh-das-id

Copy link
Copy Markdown

No description provided.

@super30admin

Copy link
Copy Markdown
Owner

Rotting Oranges (RottingOranges.java)

Strengths:

  1. Well-structured solution with clear logic flow
  2. Good variable naming and code readability
  3. Correctly handles all edge cases including empty grid scenario
  4. Proper use of BFS for level-order traversal
  5. Includes helpful comments about complexity

Areas for Improvement:

  1. The early break statements checking fresh == 0 inside the inner loops are unnecessary since the outer loop will naturally terminate when the queue is empty. These could be removed for cleaner code.
  2. Consider using Pair or a custom class instead of int[] for coordinates to improve type safety and readability (though int[] is acceptable for this problem).
  3. The neighbor variable is declared but never used - this is dead code that can be removed.

Overall, this is a solid solution that correctly solves the problem with optimal time and space complexity.

VERDICT: PASS


Employee Importance (EmployeeImportance.java)

Strengths:

  • Correctly uses a HashMap for O(1) employee lookups
  • Good use of recursion (DFS) to traverse the hierarchy
  • Clean separation of concerns (map building vs. traversal)
  • Proper handling of base case when employee has no subordinates

Areas for Improvement:

  1. The comment says "where m is the number of employees" but uses n elsewhere - be consistent with variable naming
  2. The null check subordinates == null is unnecessary given the problem constraints (subordinates is always a list, possibly empty)
  3. Consider using an iterative approach (BFS with queue) to avoid potential stack overflow issues with very deep hierarchies, though this is minor
  4. The code could be slightly more readable by combining the return statement logic

Overall, this is a solid solution that correctly solves the problem with optimal time and space complexity.

VERDICT: PASS

Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment

Labels

None yet

Projects

None yet

Development

Successfully merging this pull request may close these issues.

2 participants